1.

A mixture of CO and CO_(2) is found to have a density of 1.50" g "L^(-1) at 20^(@)C and 740 mm pressure. Calculate the composition of the mixture.

Answer»

Solution :Let the mol% of CO in mixture =X
mol%of `CO_(2)= (100-x)`
AVERAGE molecular mass `=([(x xx28)+(100-x)xx24])/(100)`
`:. ([(x xx28)+(100-x)xx24])/(100)=(dRT)/(P)""(" Because ",M=(dRT)/(P))`
`=((x xx28)+(100-x)xx24)/(100)=1.50gL^(-1)xx0.0821 L atm K^(-1) mol^(-1)xx (293K)/(100)`
mol% of `CO=43.38" and mol % of "CO_(2)=(100-x)`
`=100-43.38=56.62`.


Discussion

No Comment Found