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A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen. |
Answer» <html><body><p></p>Solution :As the mixture of `H_(2)` and `O_(2)` <a href="https://interviewquestions.tuteehub.com/tag/contains-11473" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINS">CONTAINS</a> 20% by weight of dihydrogen, therefore, if `H_(2)`=20 g, then `O_(2)`=<a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a> g <br/> `n_(H_(2))=(20)/(2)=10" <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a>", n_(O_(2))=(80)/(<a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a>)=2.5" moles"` <br/> `p_(H_(2))=(n_(H_(2)))/(n_(H_(2))+n_(O_(2)))xxP_("total")=(10)/(10+2.5)<a href="https://interviewquestions.tuteehub.com/tag/xx1-1463705" style="font-weight:bold;" target="_blank" title="Click to know more about XX1">XX1</a>" bar"=0.8" bar"`</body></html> | |