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A mixture of hydrogen and oxygen at `1` bar pressure contains `20%` of hydrogen by weight. Calculate the partial pressure of hydrogen. |
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Answer» Correct Answer - 0.8 bar Let the weight of dihydrogen be 20 g and the weight of dioxygen be 80 g. Then, the number of moles of dihydrogen, `n_(H_2)=(20)/(2)=10` moles and the number of moles of dioxygen, `n_(O_2)=(80)/(32)=2.5` moles Given, Total pressure os the mixture, `p_("total")` = 1 bar Then partial pressure of dihydrogen, `P_(H_2)=(n_(H_2))/(n_(H_2)+n_(O_2))xxP_("total")` `=(10)/(10+2.5)xx1` = 0.8 bar Hence, the partial pressure of dihydrogen is 0.8 bar. |
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