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A mixture of N_(2) and H_(2) in the molar ratio1:3 attains equilibrium when 50% of the mixture has reacted , If P is the total pressure of the mixture , then partial pressure of NH_(3) formed is

Answer» <html><body><p>`P//2`<br/>`P//3`<br/>`P//4`<br/>`P//6`</p>Solution :`{:(,N_(2),+,3 H_(2),hArr,2 NH_(3)),("Intial",1 " mole",,3 "moles",,0),("At eqm." ,1-x,,3-3x,,2 x):}` <br/> But out of4 moles of the mixture , 2 moles have reacted and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> 2 moles are <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a> .<br/> ` :. (1-x) + ( 3-3x) = 2 <a href="https://interviewquestions.tuteehub.com/tag/or4-583925" style="font-weight:bold;" target="_blank" title="Click to know more about OR4">OR4</a> x = 2 or 4 x = 2 or x = 0.5` <br/> ` :. " Total moles at equilibrium " ` <br/> ` = (1-x) + (3-3x )+ 2 x ` <br/> ` = 4 - 2 x = 4 - 1 = 3 ` <br/> No . of moles of `NH_(3)` at equilibrium = 2 x = 1<br/> ` :. p_(NH_(3)) = 1/3 xx P = P/3 `</body></html>


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