A mixture of Nitrogen and Hydrogen (1:3 mole ratio) is at an initial pressure of 200atm. If 20% of the mixture reacts by the time equilibrium is reached, the equilibrium pressure of the mixture is

A mixture of Nitrogen and Hydrogen (1:3 mole ratio) is at an initial p

1.	A mixture of Nitrogen and Hydrogen (1:3 mole ratio) is at an initial pressure of 200atm. If 20% of the mixture reacts by the time equilibrium is reached, the equilibrium pressure of the mixture is
Answer» <P>Data insufficient 180 atm 170 atm 160 atm Solution :`N_(2(g))=3H_(2(g)) harr 2NH_(3(g))` from stoichiometry 4 MOLE reactants reacted to give 2 moles of `NH_(3)` 20% of 200 atm = 40 atm reacted to give 20 atm of products (`:. P prop n`) Pressure of reactants LEFT = 200 - 40 = 160 atm Total pressure at EQULIBRIUM = 160+20=180atm