A mixture of Nitrogen and Hydrogen (1:3 mole ratio) is at an initial pressure of 200atm. If 20% of the mixture reacts by the time equilibrium is reached, the equilibrium pressure of the mixture is

A mixture of Nitrogen and Hydrogen (1:3 mole ratio) is at an initial p

1.	A mixture of Nitrogen and Hydrogen (1:3 mole ratio) is at an initial pressure of 200atm. If 20% of the mixture reacts by the time equilibrium is reached, the equilibrium pressure of the mixture is
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>Data insufficient<br/>180 atm<br/>170 atm<br/>160 atm</p>Solution :`N_(2(g))=3H_(2(g)) harr 2NH_(3(g))` <br/> from stoichiometry <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> reactants reacted to give 2 moles of `NH_(3)` 20% of 200 atm = 40 atm reacted to give 20 atm of products (`:. P prop n`) <br/> Pressure of reactants <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a> = 200 - 40 = 160 atm <br/> Total pressure at <a href="https://interviewquestions.tuteehub.com/tag/equlibrium-452655" style="font-weight:bold;" target="_blank" title="Click to know more about EQULIBRIUM">EQULIBRIUM</a> = 160+20=180atm</body></html>