A mixture of NO_(2) and N_(2)O_(4) has a vapour density of 38*3 at 300 K . What is the number of moles of NO_(2) in 100 g of the mixture ?

A mixture of NO_(2) and N_(2)O_(4) has a vapour density of 38*3 at 300

1.	A mixture of NO_(2) and N_(2)O_(4) has a vapour density of 38*3 at 300 K . What is the number of moles of NO_(2) in 100 g of the mixture ?
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>043`<br/>`44`<br/>`34`<br/>` 0<a href="https://interviewquestions.tuteehub.com/tag/rightde-437-316644" style="font-weight:bold;" target="_blank" title="Click to know more about 437">437</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Suppose `NO_(2) = x g . " Then " N_(2) O_(4) = ( 100 - x) g ` <br/> `" Moles of " NO_(2)= x/46,"Moles of " N_(2)O_(4)=(100-x)/92` <br/>`"Mole fraction of "NO_(2)(x//46)/(x//46 + ( 100 - x ) //92)` <br/> `= x/46 xx92/(100+x)=(2x)/(100+x)` <br/> Mole fraction of `N_(2)O_(4) = 1 - (2x)/(100+x) = (100 - x)/(100+x) ` <br/> Molar mass of mixture <br/> `= (2x)/(100 + x) xx 46 + ( 100-x)/(100+x) xx92 = 9200/(100+x) `<br/> `:. 9200/(100+x) = 2 xx 383 = 766`<br/> or` 766 x = 9200 = 1540 or x = 2010 g ` <br/> ` :." Moles of " NO_(2) = (20*10)/46 = 0. 437`</body></html>