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A monoprotic acid in a 0.1 M solution ionizes to 0.001 % . Its ionizationconstant is |
Answer» <html><body><p>`1.0xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) ` <br/>` 1.0 xx 10^(-6) ` <br/>` 1.0 xx 10^(-8) ` <br/>` 1.0 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>) ` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`C = 0.1 , alpha = 10 ^(-5),K_a = <a href="https://interviewquestions.tuteehub.com/tag/calpha-2020052" style="font-weight:bold;" target="_blank" title="Click to know more about CALPHA">CALPHA</a> ^(2)= 10 ^(-11) `</body></html> | |