(a). Na_(2)SO_(4) is soluble in water whereas BaSO_(4) is insoluble. Why? (b). When Mg metal is burant in air, a white powder is left behind as ash. What is the white powder?

(a). Na_(2)SO_(4) is soluble in water whereas BaSO_(4) is insoluble. W

1.	(a). Na_(2)SO_(4) is soluble in water whereas BaSO_(4) is insoluble. Why? (b). When Mg metal is burant in air, a white powder is left behind as ash. What is the white powder?
Answer» <html><body><p></p>Solution :a. The lattice enthalpy of `Na_(2)SO_(4)` is less than its hydration enthalpy whereas the lattice enthalpy of `BaSO_(4)` (because of `+2` charge of `ba^(2+))` is very higa as compared to its hydraton enthalpy. That is why `Na_(2)SO_(4)` is soluble in water whereas `BaSO_(4)` is <a href="https://interviewquestions.tuteehub.com/tag/insoluble-1045950" style="font-weight:bold;" target="_blank" title="Click to know more about INSOLUBLE">INSOLUBLE</a>. <br/> b. Magnesium on burning in air <a href="https://interviewquestions.tuteehub.com/tag/reacts-1178303" style="font-weight:bold;" target="_blank" title="Click to know more about REACTS">REACTS</a> with oxygen and nitrogen resulting in the <a href="https://interviewquestions.tuteehub.com/tag/formation-996531" style="font-weight:bold;" target="_blank" title="Click to know more about FORMATION">FORMATION</a> of `<a href="https://interviewquestions.tuteehub.com/tag/mgo-559724" style="font-weight:bold;" target="_blank" title="Click to know more about MGO">MGO</a>` and `Mg_(3)N_(2)`. <br/> `2 Mg+O_(2)rarr2MgO` <br/> `3 Mg+N_(2)rarrMg_(3)N_(2)` <br/> White powder is the mixure of `MgO` and `Mg_(3)N_(2)`.</body></html>