A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon.If the pressure of the mixture ? (Atomic mass of Ne=20 u)

A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon.If t

1.	A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon.If the pressure of the mixture ? (Atomic mass of Ne=20 u)
Answer» Solution :No. of moles of DIOXYGEN `(n_(o_(2)))=("Mass of "O_(2))/("Molar mass of "O_(2))=(70.6g)/(32 gmol^(-1))=2.21 mol` No. of moles of neon `(n_(Ne))=("Mass of" Ne)/("Molar mass of" Ne)=(167.5 g)/(20 g mol^(-1))=8.375 mol` Mole fraction of dioxygen`=(overset(n)""O_(2))/(overset(n)""O_(2)+overset(n)""He)=(2.21)/(2.21+8.375)=0.21` Mole fraction neon =1-0.21=0.79 Partial PRESSURE of `O_(2)`=Moll fraction of `O_(2)XX"Total pressure"=0.21xx25" bar"=5.25 "bar"` Partial pressure of Ne =Mole fraction of Ne`xx`Total pressure `=0.79xx25 bar=19.75 "bar"`