A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon.If the pressure of the mixture ? (Atomic mass of Ne=20 u)

A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon.If t

1.	A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon.If the pressure of the mixture ? (Atomic mass of Ne=20 u)
Answer» <html><body><p></p>Solution :No. of moles of <a href="https://interviewquestions.tuteehub.com/tag/dioxygen-954359" style="font-weight:bold;" target="_blank" title="Click to know more about DIOXYGEN">DIOXYGEN</a> `(n_(o_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)))=("Mass of "O_(2))/("Molar mass of "O_(2))=(70.6g)/(32 gmol^(-1))=2.21 mol`<br/> No. of moles of neon `(n_(Ne))=("Mass of" Ne)/("Molar mass of" Ne)=(167.5 g)/(20 g mol^(-1))=8.375 mol`<br/> Mole fraction of dioxygen`=(overset(n)""O_(2))/(overset(n)""O_(2)+overset(n)""He)=(2.21)/(2.21+8.375)=0.21` <br/> Mole fraction neon =1-0.21=0.79 <br/> Partial <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> of `O_(2)`=Moll fraction of `O_(2)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>"Total pressure"=0.21xx25" bar"=5.25 "bar"` <br/> Partial pressure of Ne =Mole fraction of Ne`xx`Total pressure `=0.79xx25 bar=19.75 "bar"`</body></html>