A network using CSMA/CD has a bandwidth of 10 Mbps. If the maximum propagation time (including the delays in the devices and ignoring the time needed to send a jamming signal, as we see later) is 25.6 μs, what is the minimum size of the frame?(a) 128 bytes(b) 32 bytes(c) 16 bytes(d) 64 bytesI had been asked this question during an online exam.I would like to ask this question from Layers in section Cryptography Overview, TCP/IP and Communication Networks of Cryptograph & Network Security

A network using CSMA/CD has a bandwidth of 10 Mbps. If the maximum pro

1.	A network using CSMA/CD has a bandwidth of 10 Mbps. If the maximum propagation time (including the delays in the devices and ignoring the time needed to send a jamming signal, as we see later) is 25.6 μs, what is the minimum size of the frame?(a) 128 bytes(b) 32 bytes(c) 16 bytes(d) 64 bytesI had been asked this question during an online exam.I would like to ask this question from Layers in section Cryptography Overview, TCP/IP and Communication Networks of Cryptograph & Network Security
Answer» Correct CHOICE is (d) 64 bytes To EXPLAIN: The MINIMUM frame transmission time is Tfr = 2 × Tp = 51.2 μs. This means, in the WORST case, a station needs to transmit for a period of 51.2 μs to detect the collision. The minimum size of the frame is 10 Mbps × 51.2 μs = 512 bits or 64 bytes. This is actually the minimum size of the frame for STANDARD Ethernet.

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