1.

A neutral atom of an element has 2 K, 8L and 5M electrons. Find out the following. (iv) Number of protons in the nucleus.

Answer»

Solution :The ELECTRONIC CONFIGURATION of the element with 2K, 8L and 5M ELECTRONS will be
`1s^2 2s^2 2p_x^2 2p_y^2 2p_z^2 3s^2 3p_x^1 3p_x^1 p_y^1 3p_z^1`
SINCE, the atom is neutral,
`:.` Number of protons = Number of electrons = ATOMIC number = 15.


Discussion

No Comment Found