A nonmetal X forms two oxides, A and B. The ratio of weight of the element X to the weight of oxygen in A and B is 7 : 20 and 7 : 16 respectively. If the molecular mass of the oxide, A is 1 08, identify A and B.

A nonmetal X forms two oxides, A and B. The ratio of weight of the ele

1.	A nonmetal X forms two oxides, A and B. The ratio of weight of the element X to the weight of oxygen in A and B is 7 : 20 and 7 : 16 respectively. If the molecular mass of the oxide, A is 1 08, identify A and B.
Answer» Solution :In 108 G of `A,7/27xx108=28g` of A is present. Since the velency of oxygen is 2, we can consider the formula of A is `X_2O_2` `:. A=(108-28)/16=5" and the formula of "` A is `X_2O_5`, Atomic weight of X 28/2 = 14 `:. "ELEMENT X is NITROGEN, and A is "N_2O_5`. Let the formula of B is `N_2O_b` Since the ratio of N and O in B is 7 : 16, the number of oxygen atoms present in B is 4[`:.28g`of nitrogen combines with 64 g of oxygen] `:. " formula of B is "N_2O_4 (or)NO_2`