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A number is selected from the first 20 natural numbers. Find the probability that it would be divisible by 3 or 7?(a) \(\frac{19}{46}\)(b) \(\frac{24}{67}\)(c) \(\frac{12}{37}\)(d) \(\frac{7}{20}\)I got this question during an interview for a job.My query is from Addition Theorem on Probability in chapter Discrete Probability of Discrete Mathematics |
Answer» Right option is (d) \(\FRAC{7}{20}\) |
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