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A parallel plate capacitor of capacitance C is connected to a battery and is charged to a potential difference V. Another capacitor of capacitance 2C is ismilarly charged to a potential difference 2V. The charging battery is now disconnected and the capacitors are connected in parallel to each other in such a way that the poistive terminal of one is connected to the negative terminal of the other. The final energy of the configuration isA. (a) zeroB. (b) `3/2CV^2`C. (c) `25/6CV^2`D. (d) `9/2CV^2`

Answer» Correct Answer - B
C and 2C are in parallel to each other.
`:.` Resultant capacity=(2C+C)`
`C_R=3C`
Net potential `=2V-V`
`V_R=V`
`:.` Final energy `=1/2C_R(V_R)^2=1/2(3C)(V)^2=3/2CV^2`


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