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A particle describes circular motion with its angular displacement `theta` at anytime `t` is given by `theta=5t-3` radian. If the radius of circular path is `2 m`, find the total acceleration of particle. |
Answer» `theta=5t-3` `omega=(d theta)/(dt)=5` `alpha=(domega)/(dt)=0` `a_(c)=omega^(2)R=(5)^(2)xx2=50 m//s^(2)` `a_(1)=Ralpha=0` Total acceleration `a=a_(c)=50 m//s^(2)` |
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