1.

A particle describes circular motion with its angular displacement `theta` at anytime `t` is given by `theta=5t-3` radian. If the radius of circular path is `2 m`, find the total acceleration of particle.

Answer» `theta=5t-3`
`omega=(d theta)/(dt)=5`
`alpha=(domega)/(dt)=0`
`a_(c)=omega^(2)R=(5)^(2)xx2=50 m//s^(2)`
`a_(1)=Ralpha=0`
Total acceleration `a=a_(c)=50 m//s^(2)`


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