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A particle executes SHM of period T and amplitude l along a rod AB of length 2l. The rod AB itself executes SHM of the same period and amplitude in a direction perpendicular to its length. Initially, both the particle and the rod are in their mean position. The path traced out by the particle will be...........

Answer» <html><body><p>a circle of radius <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a><br/>a straight line inclined at `(pi)/(4)` to the rod <br/>an ellipse<br/>a figure of eight</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> the <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> harmonic equation for the particle be `x= l sin omega t"""………."(1)` <br/> The equation of motion of rod AB, <br/> `y= l cos (omega t + <a href="https://interviewquestions.tuteehub.com/tag/phi-599602" style="font-weight:bold;" target="_blank" title="Click to know more about PHI">PHI</a>)` <br/> where rod executes angular frequency (periodic time) in y-direction with amplitude of particle. <br/> For both, at mean position `t=0" and "x= y=0` then `phi = (pi)/(2)`. <br/> `therefore y= l cos (omega t+(pi)/(2))= -l sin omega t"..........."(2)` <br/> Frqom equation (1) and (2), `y= -x`, <br/> which is the equation to a straight line at angle `(pi)/(4)` to the rod.</body></html>


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