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InterviewSolution
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A particle executing SHM has a velocity of 2 `ms^(-1)` when its displacement from mean position is 1 cm and a velocity of `1 ms^(-1)` when its displacement is 2 cm. Its amplitude of oscillationisA. 5 cmB. `sqrt(5) cm`C. 3 cmD. `sqrt(7) cm` |
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Answer» Correct Answer - B `(V_(1))/(V_(2))=sqrt((A^(2)-y_(1)^(2))/(A^(2)-y_(2)^(2))),(2)/(1)=sqrt((A^(2)-1)/(A^(2)-2^(2)))` `4A^(2)-16=A^(2)-1` `3A^(2)=15,A^(2)=5` `A=sqrt((2^(2)xx2^(2)-1^(2)xx1^(2))/(2^(2)-1))` `=sqrt((15)/(3))=sqrt(5)` By shortcut method, `A=sqrt(v_(1)^(2)+v_(2)^(2))` |
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