A particle is droped from a height H. The de-broglie wavelength of the particle as a function of height is proportional toA. `H`B. `H^(1//2)`C. `H^(0)`D. `H^(-1//2)`

A particle is droped from a height H. The de-broglie wavelength of the

1.	A particle is droped from a height H. The de-broglie wavelength of the particle as a function of height is proportional toA. `H`B. `H^(1//2)`C. `H^(0)`D. `H^(-1//2)`
Answer» Correct Answer - D Velocity of a body falling from a height `H` is given by `v=sqrt(2gH)` We know that de-broglie wavelength `lambda=h/(mv)=h/(msqrt(2gH)) rArr =h/(msqrt(2g)sqrtH)` Here,`h/(msqrt2g)` is a constant `phi` say `K` So, `lambda=K1/sqrtH rArr prop 1/sqrtH rArrlambda prop H^(-1//2)`

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A particle is droped from a height H. The de-broglie wavelength of the particle as a function of height is proportional toA. `H`B. `H^(1//2)`C. `H^(0)`D. `H^(-1//2)`

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