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A particle is executing simple harmonic motion with an amplitude of 2m . The difference in the magnitudes of its maximum acceleration and maximum velocity is 4. The time period of its oscilation and its velocity when it is 1m away from the mean position are respectively. |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2s-301125" style="font-weight:bold;" target="_blank" title="Click to know more about 2S">2S</a>, 2sqrt(3)ms^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>/(<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>)s,4sqrt(3)ms^(-1)`<br/>`(22)/7s,2sqrt(3)ms^(-1)`<br/>`(44)/7s,4sqrt(3)ms^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |