1.

A particle is given an initial velocity of 20m/s. acceleration of the particle changes with time and its variation is shown in the following figure.

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Solution :Area under THEACCELERATION - time graph representsthe change in VELOCITY. Area above the time axis is takenas positive andbelow the timeaxis , it is taken as negative . To acquireinitial velocityagain ,changein velocitymust be zero . Ifwe canextend the graph for 6s then we can see that TOTALAREA becoms zero DUETO equal amounts of positive and negative areas. Henceparticle acquires BACK its initialvelocity att = 6s.
Answer is 6 .


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