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A particle is moving with a uniform acceleration `4 m s^(-2)` for time `2 second` and then `5 m s^(-20` for time `3 seconds`. What is the average acceleration of particle during motion. |
Answer» Hence, `a_(1) =4 ms^(-2) , t_(1) =2 s, a_(2) =5 ms^(-2) , t_(2) =3 s` `a_(av) =(a_(1)t_(1) +a_(2) t_(2))/(t_(1) +t_(2)) =(4xx 2+ 5 xx 3)/(2 =3) = 23/5 =4.6 ms^(-2)`. |
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