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A particle is projected with velocity u at an angle theta with the horizontal at t=0.What is the magnitude of change in thevelocity of the particle when it is atmaximum height​

Answer» <html><body><p>At the <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> of <a href="https://interviewquestions.tuteehub.com/tag/projection-1169328" style="font-weight:bold;" target="_blank" title="Click to know more about PROJECTION">PROJECTION</a>, the particle's speed is u and the particle's speed at the <a href="https://interviewquestions.tuteehub.com/tag/highest-1022683" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHEST">HIGHEST</a> <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> the particle's speed is ucosθ. So, the change in speed is,Δu=u−ucosθNow, the initial velocity is,u =ucosθ i^ +usinθ j^ and the final velocity (at highest point) is,v =ucosθ i^ Therefore, the change in velocity is,Δ v = u − v =ucosθ i^ +usinθ j^ −ucosθ i^ =usinθ j^ ⇒∣Δ v ∣=usinθ</p></body></html>


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