1.

A particle is subjected to two `SHMs x_(1) = A_(1) sin omegat` and `x_(2) = A_(2)sin (omegat +(pi)/(4))`. The resultant `SHM` will have an amplitude ofA. `(A_(1)+A_(2))/(2)`B. `sqrt(A_(1)^(2)+A_(2)^(2))`C. `sqrt(A_(1)^(2)+A_(2)^(2)+sqrt(2)A_(1)A_(2))`D. `A_(1)A_(2)`

Answer» Correct Answer - C
`A = sqrt(A_(1)^(2)+A_(2)^(2)+2A_(1)A_(2)cosphi)`


Discussion

No Comment Found

Related InterviewSolutions