A particle moves along a straight line retardation a = ksqrt(v) [ k is a positive constant ]. The velocity of the particle at time t = 0 is u. How far would the particle move before coming to rest ?

A particle moves along a straight line retardation a = ksqrt(v) [ k is

1.	A particle moves along a straight line retardation a = ksqrt(v) [ k is a positive constant ]. The velocity of the particle at time t = 0 is u. How far would the particle move before coming to rest ?
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(2)/(<a href="https://interviewquestions.tuteehub.com/tag/3k-310983" style="font-weight:bold;" target="_blank" title="Click to know more about 3K">3K</a>)usqrt(<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>);(2)/(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)sqrt(u)`</body></html>