A particle moves along a straight line retardation a = ksqrt(v) [ k is a positive constant ]. The velocity of the particle at time t = 0 is u. How far would the particle move before coming to rest ?

A particle moves along a straight line retardation a = ksqrt(v) [ k is

1.	A particle moves along a straight line retardation a = ksqrt(v) [ k is a positive constant ]. The velocity of the particle at time t = 0 is u. How far would the particle move before coming to rest ?
Answer» ANSWER :`(2)/(3K)usqrt(U);(2)/(K)sqrt(u)`