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A particle moves along the side of a square of length ‘l’ starting from A and reaches the opposite comer ‘C’ by travelling from A to B and B to C in time the average velocity isA) \(\cfrac{2l}t\)B) \(\cfrac{l}{\sqrt{2}t}\)C) ZeroD) \(\cfrac{\sqrt{2l}}t\) |
Answer» D) \(\cfrac{\sqrt{2l}}t\) |
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