A particle moves along the X-axis as `x=u(t-2s)=at(t-2)^2`.A. The initial velocity of the particle is uB. The acceleration of the particle is aC. The acceleration of the particle is 2aD. At `t=2s` particle is at the origin

A particle moves along the X-axis as `x=u(t-2s)=at(t-2)^2`.A. The init

1.	A particle moves along the X-axis as `x=u(t-2s)=at(t-2)^2`.A. The initial velocity of the particle is uB. The acceleration of the particle is aC. The acceleration of the particle is 2aD. At `t=2s` particle is at the origin
Answer» Correct Answer - C::D `x=u(t-2)+a(t-2)^(2)`…(i) `v=(dx)/(dt)=u+2a(t-2)` Therefore `v(0)=u-4a` `a=(d^(2)x)/(dt^(2))=2a" "` Hence [C] `x(2)=0`[From (i)]. Hence [D]

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A particle moves along the X-axis as `x=u(t-2s)=at(t-2)^2`.A. The initial velocity of the particle is uB. The acceleration of the particle is aC. The acceleration of the particle is 2aD. At `t=2s` particle is at the origin

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