InterviewSolution
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InterviewSolution
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A particle moves in a circle of radius `20 cm`. Its linear speed is given by `v = 2t` where `t` is in seconds and `v` in `m s^-1`. ThenA. The radial acceleration at `t = 2 s` is `80 m s^-2`.B. Tangential acceleration at `t = 2 s` is `2 m s^-2`.C. Net acceleration at `t = 2 s` is greater than `80 m s^-2`.D. Tangential acceleration remains constant in magnitude. |
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Answer» Correct Answer - A::B::C::D (a.,b.,c.,d.) `v = 2t, a_c = (v^2)/( r) = ((2 t)^2)/(0.2) = 20 t^2 = 20 xx 2^2 = 80 ms^-2` `a_t = (dv)/(dt) = 2 ms^-2` Net acceleration `a = sqrt(a_c^2 + a_t^2) gt 80 ms^-2`. |
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