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A particle moves in the X-Y plane under the action of a force vec(F) such that the value of its linear momentum (vec(P)) at any time .t., and its components are P_(X) = 2 cos t, P_(Y) = 2 sin t. According to defination of force vec(F) = (d vec(P))/(dt) The angle .theta. between vec(F) and vec(P) at a given time .t. will be

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> = 0^(@)`<br/>`theta = <a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)`<br/>`theta = <a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^(@)`<br/>`theta = 180^(@)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>


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