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A particle moves in the x−y plane under the action of a force →F such that the value of its linear momentum →p at any instant is →p=2(cost^i+sint^j). The angle θ between →F and →p is |
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Answer» A particle moves in the x−y plane under the action of a force →F such that the value of its linear momentum →p at any instant is →p=2(cost^i+sint^j). The angle θ between →F and →p is |
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