InterviewSolution
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InterviewSolution
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A particle moves on a circle of radius `r` with centripetal acceleration as function of time as `a_c = k^2 r t^2`, where `k` is a positive constant. Find the following quantities as function of time at an instant : (a) The speed of the particle (b) The tangential acceleration of the particle ( c) The resultant acceleration, and (d) Angle made by the resultant with tangential direction.A. `kt^(2)`B. `kr`C. `krsqrt(k^(2)t^(4)+1)`D. `krsqrt(k^(2)t^(2)-1)` |
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Answer» Correct Answer - C From given eqution `omega=kt`, `alpha=(domega)/(dt)=k,a_(t)=ra,a=sqrt(a_(c)^(2)+a_(t)^(2))` |
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