InterviewSolution
Saved Bookmarks
| 1. |
A particle of charge `q` and mass `m` moves in a circular orbit of radius `r` with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends onA. `(q)/(2m)`B. `(q omega r^(2))/(2)`C. `(q omega)/(2m r^(2))`D. `( q omega r^(2))/(2m) ` |
|
Answer» Correct Answer - A The relation between magnetic moment `(mu_l)` and angular momentum (L) is ` mu_l=-(q)/(2m)L` `implies (mu_l)/L=(q)/(2m)` The negative sign indicates that the angular momentum of the electron is opposite in direction to the magnetic moment. |
|