1.

A particle of charge `q` and mass `m` moves in a circular orbit of radius `r` with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends onA. `(q)/(2m)`B. `(q omega r^(2))/(2)`C. `(q omega)/(2m r^(2))`D. `( q omega r^(2))/(2m) `

Answer» Correct Answer - A
The relation between magnetic moment `(mu_l)` and angular momentum (L) is ` mu_l=-(q)/(2m)L`
`implies (mu_l)/L=(q)/(2m)`
The negative sign indicates that the angular momentum of the electron is opposite in direction to the magnetic moment.


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