InterviewSolution
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InterviewSolution
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A particle of mass `m`and charge `q`, moving with velocity `v` enters Region `II` normal to the boundary as shown in the figure. Region `II` has a uniform magnetic field `B` perpendicular to the plane of the paper . The length of the region `II` is `l`. Choose the correct choice(s).A. The particle enters regions III only if its velocity `V gt (qlB)/(m)` .B. The particle enters regions III only if its velocity `V gt (qlB)/(m)` .C. Path length of the particle in region II is maximum when velocity `V = (qlB)/(m)`D. Time spent in region II is same for any velocity `V` as long as the particle returns to region I . |
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Answer» Correct Answer - `A,C,D` In region II the particle follows a circular path of radius ` r = (mv)/(qB)` Therefore, the particle can enter III,ifr gt l i.e if `v gt (qBl)/(m)` In regin II the maximum path length is `r =l` which gives `v =(qBl)/(m)` The time period of the circular motion is ` T = (2pir)/(v) = (2pi)/(v) xx (mv)/(qB) = (2pi)/(qB)` The particle will return to region I if the time spent by in region II is `(T)/(2) =(pim)/(qB)` which is indepedndent of the velocity Hence the correct choices are `(A)` `(C)` and `(D)` . |
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