A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a is varying with time t as a = k^(2)rt^(2) where k is a constant. What is the power delivered to the particle by the forces acting on it.

A particle of mass m is moving in a circular path of constant radius r

1.	A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a is varying with time t as a = k^(2)rt^(2) where k is a constant. What is the power delivered to the particle by the forces acting on it.
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`Asa_(c)=(v^(2)//<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)so(v^(2)//r)=k^(2)rt^(2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> energy `K = (1)/(2) mv^(2) = (1)/(2) mk^(2)r^(2)t^(2)` <br/> Now by work - Enetgy Theorem <br/> `W=DeltaK=(1)/(2)mk^(2)r^(2)t^(2)-0rArrP=(dw)/(dt)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> P = (d)/(dt) = (1)/(2) mk^(2)r^(2)t^(2) =mk^(2)r^(2)t`</body></html>