A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to - (K//r^(2)), where K is constant. What is the total energy of the particle ?

A particle of mass m is moving in a horizontal circle of radius r, und

1.	A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to - (K//r^(2)), where K is constant. What is the total energy of the particle ?
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)/( <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)`<br/>`-(k)/(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>)`<br/>`-(k)/(r )`<br/>`(k)/(2r)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>