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InterviewSolution
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A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to `(-K//r^(2))`, where k is a constant. The total energy of the particle is -A. `KE = ((k)/(2r)), PE = - ((k)/(r)), ME = - ((k)/(2r))`B. `KE = ((k)/(2r)), PE = - ((k)/(2r)), ME =` zeroC. `KE =` zero, PE = zero, ME = zeroD. `KE = ((k)/(r)), PE = - ((k)/(2r)), ME = ((k)/(2r))` |
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Answer» Correct Answer - A |
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