InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to `v(x) = beta x^(-2 n)` where `beta` and `n` are constant and `x` is the position of the particle. The acceleration of the particle as a function of `x` is given by.A. (a) ` ` -2 n beta^2 x^(-4n-1)`B. (b) ` `-2 beta^(2)x^(-2n+1)`C. (c ) ` - 2 n beta^2 x^(-4) n+ 1)`D. (d) ` -2 n beta^2 x^(-2n-1)` |
|
Answer» Correct Answer - A Here `v = beta x^(-2n) ` ` :. ` (dv)/(dx) =- 2n -1 `, As ` a = (dv)/(dt) = (dv)/(dx) xx (dx)/(dt)` ` or ` a = ( v dv) /(dx) = beta x^(-2n) xx -2 n beta x ^(-2n-1)` ` a=- 2 n beta^2 x^(-4n-1)` . |
|