A particle traversed half of the distance with a velocity of V_(0). The remaining parts of the distance was covered with velocity V_(1), for half of the time and with V_(2) for other half of the time. Find the mean velocity of the particle averaged and the whole time of motion

A particle traversed half of the distance with a velocity of V_(0). Th

1.	A particle traversed half of the distance with a velocity of V_(0). The remaining parts of the distance was covered with velocity V_(1), for half of the time and with V_(2) for other half of the time. Find the mean velocity of the particle averaged and the whole time of motion
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C03_SLV_002_S01.png" width="80%"/> <br/> Average <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> for the second <a href="https://interviewquestions.tuteehub.com/tag/half-1014510" style="font-weight:bold;" target="_blank" title="Click to know more about HALF">HALF</a> distance = `(v_(1)(t)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)+v_(2)(t)/(2))/((t)/(2)+(t)/(2))=(v_(1)+v_(2))/(2)` <br/> Average velocity for the first half distance = `V_(0)` (`because` it is constant) <br/> Average velocity for total path <br/> `=(2v_(0)((v_(1)+v_(2))/(2)))/(v_(0)+(v_(1)+v_(2))/(2))=(2v_(0)(v_(1)+v_(2)))/(v_(1)+v_(2)+2v_(0))`</body></html>