A perfect gas goes from state A to state B by absorbing 8xx10^(5)J of heat and doing 6.5xx10^(5)J of external work. It is now transferred between the same two states in another process in which it absorbs 10^(5)J of heat. In second process. Find the work done in the second process.

A perfect gas goes from state A to state B by absorbing 8xx10^(5)J of

1.	A perfect gas goes from state A to state B by absorbing 8xx10^(5)J of heat and doing 6.5xx10^(5)J of external work. It is now transferred between the same two states in another process in which it absorbs 10^(5)J of heat. In second process. Find the work done in the second process.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :According to the <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of thermodynamics <br/> `DeltaU=DeltaQ-DeltaW` <br/> In the first process `DeltaU=8xx10^(5)-6.5xx10^(5)=1.5xx10^(5)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>` <br/> Now `DeltaU`, being a state function, remains the same in the second process, <br/> `DeltaW=DeltaQ-DeltaU=1 xx10^(5)-1.5xx10^(5)` <br/> `DeltaW=-0.5xx10^(5)J` <br/> The negative sign shows that work is doen on the <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a>.</body></html>