A person of mass 60 kg is in a lift. The change in the apparent weight of the person, when the lift moves up with an acceleration of 2ms^(-2) and then down with an acceleration of 2ms^(-2) is ("take g = "10 m//sec^(2))

A person of mass 60 kg is in a lift. The change in the apparent weight

1.	A person of mass 60 kg is in a lift. The change in the apparent weight of the person, when the lift moves up with an acceleration of 2ms^(-2) and then down with an acceleration of 2ms^(-2) is ("take g = "10 m//sec^(2))
Answer» 120 N 240 N 480 N 720 N Solution :`w_(1)=m(g+a), w_(2)=m(g-a)`