A person of mass 60 kg is in a lift. The change in the apparent weight of the person, when the lift moves up with an acceleration of 2ms^(-2) and then down with an acceleration of 2ms^(-2) is ("take g = "10 m//sec^(2))

A person of mass 60 kg is in a lift. The change in the apparent weight

1.	A person of mass 60 kg is in a lift. The change in the apparent weight of the person, when the lift moves up with an acceleration of 2ms^(-2) and then down with an acceleration of 2ms^(-2) is ("take g = "10 m//sec^(2))
Answer» <html><body><p>120 N<br/>240 N<br/>480 N <br/><a href="https://interviewquestions.tuteehub.com/tag/720-334419" style="font-weight:bold;" target="_blank" title="Click to know more about 720">720</a> N</p>Solution :`w_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=m(g+a), w_(2)=m(g-a)`</body></html>