A person travelling on a straight line moves with a uniform velocity v

1.	A person travelling on a straight line moves with a uniform velocity v1 for some time and with uniform velocity v2 for the next equal time. The average velocity is v given by (a) v =(v1+v2)/2(b) v=√v1v2(c) 2/v=1/v1+1/v2(d) 1/v=1/v1+1/v2
Answer» (a) v = (v₁ + v₂)/2. Explanation: Let t be the time related to each velocity. Total distance travelled =v₁t+v₂t. Total time taken=2t. Hence average velocity = v₁t+v₂t/2t =(v₁+v₂)/2.

A person travelling on a straight line moves with a uniform velocity v1 for some time and with uniform velocity v2 for the next equal time. The average velocity is v given by (a) v =(v1+v2)/2(b) v=√v1v2(c) 2/v=1/v1+1/v2(d) 1/v=1/v1+1/v2

Answer»

(a) v = (v₁ + v₂)/2.

Explanation:

Let t be the time related to each velocity. Total distance travelled =v₁t+v₂t. Total time taken=2t. Hence average velocity = v₁t+v₂t/2t =(v₁+v₂)/2.

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A person travelling on a straight line moves with a uniform velocity v1 for some time and with uniform velocity v2 for the next equal time. The average velocity is v given by (a) v =(v1+v2)/2(b) v=√v1v2(c) 2/v=1/v1+1/v2(d) 1/v=1/v1+1/v2

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