A photon of wavelength 1.4 Å collides with an electron. After collision, the wavelength of the photon is found to be 2.0 Å. Calculate the energy of the scattered electron.

A photon of wavelength 1.4 Å collides with an electron. After collisi

1.	A photon of wavelength 1.4 Å collides with an electron. After collision, the wavelength of the photon is found to be 2.0 Å. Calculate the energy of the scattered electron.
Answer» Solution :ENERGY of the photon before COLLISON `= hv = (HC)/(lamda)` Energy of the photon after collision `= hv' = (hc)/(lamda')` Difference of energy is imparted to the electron. Hence, energy of the scattered electron `= (hc)/(lamda) - (hc)/(lamda') = hc ((1)/(lamda)- (1)/(lamda'))` `= (6.626 xx 10^(-34) J s) (3 xx 10^(8) m s^(-1)) xx((1)/(1.4 xx 10^(-10)m) - (1)/(2.0 xx 10^(-10) m))` `= (6.626 xx 10^(-34)Js) (3 xx 10^(8) ms^(-1)) xx ((2.0 - 1.4) xx 10^(-10) m^(-1))/((1.4 xx 10^(-10)) (2.0 xx 10^(-10))) = 4.26 xx 10^(-16) J`