A photon with a wavelength of 4000A^@ is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I_2 molecule is 246.5 kJ/mol

A photon with a wavelength of 4000A^@ is used to break the iodine mole

1.	A photon with a wavelength of 4000A^@ is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I_2 molecule is 246.5 kJ/mol
Answer» `8%` `12%` `17%` `25%` Solution :Energy of ONE PHOTON `=(12400)/(4000) = 3.1 eV` Energy supplied by one mole photon in KJ/mole `=3.1 xx 1.6 xx 10^(-19) xx 10^(23) xx 10^(-3) = 297 `KJ `"mol"^(-1)` `therefore` of energy converted to K.E. `=(297 - 246.5)/(297)= 17%`