A photon with a wavelength of 4000A^@ is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I_2 molecule is 246.5 kJ/mol

A photon with a wavelength of 4000A^@ is used to break the iodine mole

1.	A photon with a wavelength of 4000A^@ is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I_2 molecule is 246.5 kJ/mol
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>%`<br/>`12%`<br/>`17%`<br/>`25%`</p>Solution :Energy of <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> <a href="https://interviewquestions.tuteehub.com/tag/photon-599910" style="font-weight:bold;" target="_blank" title="Click to know more about PHOTON">PHOTON</a> `=(12400)/(4000) = 3.1 eV` <br/>Energy supplied by one mole photon in KJ/mole `=3.1 xx 1.6 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/19-280618" style="font-weight:bold;" target="_blank" title="Click to know more about 19">19</a>) xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>) xx 10^(-3) = 297 `KJ `"mol"^(-1)` <br/>`therefore` of energy converted to<br/>K.E. `=(297 - 246.5)/(297)= 17%`</body></html>