InterviewSolution
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InterviewSolution
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A physical parameter `a` can be determined by measuring the parameters `b, c, d, and e` using the relation `a=b^(alpha)c^(beta)//d^(gamma)e^(delta)`. If the maximum errors in the measurement of `b, c , d, and e are b_(1) %,c_(1)% ,d_(1)% , and e_(1) %`, then the maximum error in the value of `a` determined by the experminent. |
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Answer» ` a = b^(alpha) c ^(beta)//d^(gamma) e^(delta)` So maximum error in `a` is given by `(( Delta a)/( a) xx 100)_(max) = alpha . (Delta b)/(b) xx 100 + beta . ( Delta c)/( c ) xx 100 + gamma . ( Delta d)/( d) xx 100 + delta . ( Delta e)/( e) xx 100 = ( alpha b_(1) + beta c_(1) + gamma d_(1) + delta e_(1))%` |
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