1.

A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV The wavelength associated with the electron will be

Answer»

double in the SECOND case than in the FIRST case
double in the first case than in the second case
1.4 TIMES in the second case than in the first case
1.4 times in the first case than in the second case

Solution :`lamda = (H)/(mv) :. (lamda_(1))/(lamda_(2)) = (v_(2))/(v_(1)) = 1.4, " i.e., " lamda_(1) = 1.4 lamda_(2)`


Discussion

No Comment Found