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A `pi` shaped metal frame is located in a uniform magnetic field perpendicular to the plane of the conductor and varying with time at the rate `(dB//dt)=0.I0T//sec` . A conducting connector starts moving with an acceleration `a=I0cm//sec^(2)` along the parallel bars of the frame. The lenght o0f the connector is equal to `l=20cm` . Find the emf induced in the loop `t=2sec` after the beginnig of the motion, if at the moment `t=0` the loop area and the magnetic induction are equal to zero. The inductance of the loop is to be neglected. |
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Answer» The flux through the loop changes due to the variarion in `vec(B)` with time and also due to the movement of the connector. So, `xi_(In) = |(d(vec(B).vec(S)))/(dt)| = |(d(BS))/(dt)|` as `vec(S)` and `vec(B)` are colliniear But, `B`, after `t` sec of begining of motion = `Bt`, and `S` becomes `= l (1)/(2) w t^(2)`, as connector starts moving from rest with a constant accelertion `w`. So, `xi_("ind") = (3)/(2) B l w t^(2)` |
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