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A pieceof plumber's solder weighting 3.0 gm was dissolved in dilute nitric acid, then treated with dilute H_(2)SO_(4) . This precipatated the lead as PbSO_(4) which after washing and dryingweighted 2.98 gm. The solution was then neutralized to precipatatestannic acid, which was decomposed by heating, yielding 1.27 gm SnO_(2) . What is the analysis of the solder? (Pb=207.2 amu, Sn=118.7 amu)

Answer» <html><body><p>66.7 % <a href="https://interviewquestions.tuteehub.com/tag/pb-597752" style="font-weight:bold;" target="_blank" title="Click to know more about PB">PB</a>, 33.3% Sn<br/>33.3% Pb, <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> gm Sn<br/>1 gm Pb, 2 gm Sn<br/>2 gm Pb, 1 gm Sn</p>Answer :A::D</body></html>


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