A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0 ^(@)C. As it does so, it absorbs 208 J of heat.The values of q and w for the process will be (R = 8.314 J mol^(-1)K^(-1)) (In 7.5 = 2.01)

A piston filled with 0.04 mol of an ideal gas expands reversibly from

1.	A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0 ^(@)C. As it does so, it absorbs 208 J of heat.The values of q and w for the process will be (R = 8.314 J mol^(-1)K^(-1)) (In 7.5 = 2.01)
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> = + 208 J, w = + 208 J`<br/>`q = + 208 J, w = - 208 J`<br/>`q = - 208 J, w = - 208 J`<br/>`q = - 208 J, w = + 208 J`</p>Solution :Since it absorbs heat q = +<a href="https://interviewquestions.tuteehub.com/tag/280-299547" style="font-weight:bold;" target="_blank" title="Click to know more about 280">280</a> K <br/> Since the process is isothermal `<a href="https://interviewquestions.tuteehub.com/tag/deltau-2053495" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAU">DELTAU</a> = <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>` <br/> From first law of thermodynamics, <br/> `DeltaU = q + w` <br/> `0 = 208 + w or w = -208 J`</body></html>