1.

A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0 ^(@)C. As it does so, it absorbs 208 J of heat.The values of q and w for the process will be (R = 8.314 J mol^(-1)K^(-1)) (In 7.5 = 2.01)

Answer»

`Q = + 208 J, w = + 208 J`
`q = + 208 J, w = - 208 J`
`q = - 208 J, w = - 208 J`
`q = - 208 J, w = + 208 J`

Solution :Since it absorbs heat q = +280 K
Since the process is isothermal `DELTAU = 0`
From first law of thermodynamics,
`DeltaU = q + w`
`0 = 208 + w or w = -208 J`


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