InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A plank of mass `M` is placed on a smooth hroizonal surface. Two light identical springs each of stiffness `k` are rigidly connected to structs at the ends of the plank as shown. When the spring are in their unextended position the distance between their free ends is `3l`. a block of mass `m` is placed on the plank and pressed aganist one of the springs so that it is compressed by `l`. To keep the blocks at rest it is connected to the strut by means of a light string, initially the syetem is at rest. Now the string is burnt. Maximum displacement of plank is:A. `(ml)/(m+M)`B. `(5ml)/(m+M)`C. `(3ml)/(m+M)`D. `(2ml)/(m+M)` |
|
Answer» Correct Answer - B (1) `CM` remains at rest, block moves `5t` on plank when system comes to rest `-m [5l - Deltax] +M Deltax = 0, Deltax = (5ml)/(m+M)` (2) In `CM` frame `(1)/(2) ((m.M)/(m+M)) v_(m//M)^(2) = (1)/(2) kl^(2)` `V_(v//M) = sqrt(((M+m)/(Mm)))kl` (3) Consider motion of block w.r.t. plank `a_(M) = (kx)/(M)` right ward, `F =- (kx +ma_(M))` or `(d^(2)x)/(dt^(2)) = ((k)/(m)x+a_(M)) = - k ((1)/(M)+(1)/(M))x omega^(2) = (pi)/(2) sqrt((Mm)/((m+m)k))` Time to get the spring relaxed is `t_(1) = (pi)/(2) sqrt((Mm)/(M+m)k)` Time taken by block to travel `3l` between springs `=(3l)/(v_(m//M)) =(3l)/(sqrt((k(M+m))/(Mm))l)` Time period of oscillation of block `=2 [2t_(1)+ (3l)/(sqrt((k(M+m)Mm)/(Mm))l)] = (2pi +6) sqrt((Mm)/(k(M+m))` |
|