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A point mass is orbiting a significant mass M lying at the focus of the elleptical orbit having major and minor axes given by 2a and 2b respectively. Let r be the distance between the mass M and the point of major axis. The velocity of the particle can be given as |
Answer» <html><body><p>`(ab)/(2r) sqrt((<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(a^(3)))`<br/>`(ab)/rsqrt((GM)/(b^(3)))`<br/>`(ab)/rsqrt((GM)/(a^(3)))`<br/>`(2ab)/rsqrt((GM)/(((a+b)/2)^(2)))`</p>Solution :on stopping, the satellite will fall along the radius `<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>` of the orbit which can be regarded as a limiting case of an <a href="https://interviewquestions.tuteehub.com/tag/ellipse-450431" style="font-weight:bold;" target="_blank" title="Click to know more about ELLIPSE">ELLIPSE</a> with semi-major axis `r/2` Using kepler's <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> `T^(2)propr^(3)` <br/> time of fall `(T')/2=T/(2sqrt(8))=(sqrt(2)T)/8`</body></html> | |