A point moves along an arc of a circle of radius R. Its velocity depends on the distance covered s as `v=asqrts`, where a is a constant. Find the angle `alpha` between the vector of the total acceleration and the vector of velocity as a function of s.A. `tan alpha=R/(2s)`B. `tan alpha=(2a)/R`C. `tan alpha=(2R)/s`D. `tan alpha=s/(2R)`

A point moves along an arc of a circle of radius R. Its velocity depen

1.	A point moves along an arc of a circle of radius R. Its velocity depends on the distance covered s as `v=asqrts`, where a is a constant. Find the angle `alpha` between the vector of the total acceleration and the vector of velocity as a function of s.A. `tan alpha=R/(2s)`B. `tan alpha=(2a)/R`C. `tan alpha=(2R)/s`D. `tan alpha=s/(2R)`
Answer» Correct Answer - B `tan alpha=v^(2)/Rxx1/(dv//dt)=(a^(2)s)/(Rav//2sqrt(s))=(2s)/R`

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